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(C) The structure of the compound is $H_2C=C=CH-CHO$.$1$. The terminal $CH_2$ carbon is bonded to two hydrogens and one double bond,so it is $sp^2$ hy

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$0-3-1$

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(C) The structure of the compound is $H_2C=C=CH-CHO$.$1$. The terminal $CH_2$ carbon is bonded to two hydrogens and one double bond,so it is $sp^2$ hybridized.$2$. The central carbon in the allene system $(C=C=C)$ is bonded to two double bonds,so it is $sp$ hybridized.$3$. The $CH$ carbon is bonded to one hydrogen,one double bond,and one single bond,so it is $sp^2$ hybridized.$4$. The carbonyl carbon $(CHO)$ is bonded to one hydrogen and one double bond,so it is $sp^2$ hybridized.Total count:$sp^3$ carbons: $0$$sp^2$ carbons: $3$$sp$ carbons: $1$Therefore,the correct sequence is $0-3-1$.

List-$I$	List-$II$
$A$. Ethane	$1$. $2 \ sp$ carbons
$B$. Ethylene	$2$. $6 \ sp^2$ carbons
$C$. Acetylene	$3$. $2 \ sp^3$ carbons
$D$. Benzene	$4$. $2 \ sp^2$ carbons
	$5$. $1 \ sp$ and $1 \ sp^2$ carbons

Select the response that correctly identifies the number of carbon atoms of each type of hybridization in the compound given below:
$H_2C=C=CH-CHO$
(Order: $sp^3 - sp^2 - sp$)

Similar Questions

In the compound $CH_2=CH-CH_2-C \equiv CH$,what is the hybridization type of the $C_2-C_3$ bond?

Match the following lists:
List-$I$ List-$II$
$A$. Ethane $1$. $2 \ sp$ carbons
$B$. Ethylene $2$. $6 \ sp^2$ carbons
$C$. Acetylene $3$. $2 \ sp^3$ carbons
$D$. Benzene $4$. $2 \ sp^2$ carbons
$5$. $1 \ sp$ and $1 \ sp^2$ carbons

In the reaction,the hybridisation states of carbon atoms $1, 2, 3, 4$ are:
$Br-CH=CH-Br \xrightarrow[Catalyst]{H_2} Br-CH_2-CH_2-Br$

Which of the following bonds is most acidic?

The hybridisations of carbon-$2$ in $P$ and $Q$ are respectively:

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Select the response that correctly identifies the number of carbon atoms of each type of hybridization in the compound given below:$H_2C=C=CH-CHO$(Order: $sp^3 - sp^2 - sp$)